I apologize with the order! However I need help on question 3 of my
This report must be an independentlyYour lab mark (out of 10) will be determined by the pre-lab, interactive video, and this report.1. Calculate the % yield of the ammonium tartrate salt crystals you filtered, based off the originalmass of racemic amine you started with (page 18 in the manual).NOTE: the density of the liquid amine is 0.94 g/ml.* * *The experimental mass of the collected (-)-amine-(+)-tartrate salt was found to be = 7.89 qUse the following equation to help you:R-NH2 + C4H606 – R-NH3+-tartrateracemic aminetartaric acid121 g/mol150 g/molammonium tartrate salt- 392 9/ mol-(+ ) – tartanc acid = 12.093.) (+ ) – a -phenylethylamine(* ) : a-phenylethylamine- (racemic) = 10 mL(racemic )Density of liquid amine= 0. 94, 9 / ml.is the limiting reagentDit tartanic acid .(4.) (070 7 7) . 392 9 / mol ) = 30mol12.09= 0.0 8 mol5)actual yield = 7. 89 9 to150 g/ mol( Jamine – (+) tartrate salt( I ) – 9- phenylethylamine ( rakemic ) :6. )% yield :7. 89gX 10Oml X. 0.94 9 / ml = 9:4930, 1849)9. 49121 g/ mol= 0. 077 mol2. Hopefully the % yield from question 1 was 50% or less. Why would a percentage yield greaterthan 50% be undesirable in this experiment?A percentage yield greater than 50 % would be undesirable inexperiment, because if a racemic mixture is present, it meeit has a 50:50 ratio ( with the, 2 enantiomers). Thereforepurpose of this expenment is to extract for one product coneThis in turn, would have a lower / yield than 50%, be” the yield percentage does not include the other en
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